A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 text ms-2, the tension in the rope is (taking g=10ms-2 ):

Question

A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 text ms-2, the tension in the rope is (taking g=10ms-2 ): (A) 250 N (B) 490 N (C) 980 N (D) 1960 N

Tardigrade Admin · Accepted Answer

When helicopter is rising upward the tension in the rope is given by T=m(g+a) (Where a is acceleration of helicopter by which it is rising) Given: Mass of the person m = 70 kg accelerations a=4m/s2, g=10m/s2 Now, putting the given values in Eq. (i), we have T=70 text (10+4 text)=70× 14=980 text N

Q. A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4ms−2, the tension in the rope is (taking g=10ms−2 ):

250 N

490 N

980 N

1960 N

When helicopter is rising upward the tension in the rope is given by T=m(g+a) (Where a is acceleration of helicopter by which it is rising) Given: Mass of the person m = 70 kg accelerations a=4m/s2,g=10m/s2 Now, putting the given values in Eq. (i), we have T=70 (10+4)=70×14=980N

Q. A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration $4 m s^{- 2},$ the tension in the rope is (taking $g = 10 m s^{- 2}$ ):