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  4. A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 text ms-2, the tension in the rope is (taking g=10ms-2 ):

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Q. A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration $ 4\text{ }m{{s}^{-2}}, $ the tension in the rope is (taking $ g=10m{{s}^{-2}} $ ):

EAMCETEAMCET 1999

Solution:

When helicopter is rising upward the tension in the rope is given by $ T=m(g+a) $ (Where a is acceleration of helicopter by which it is rising) Given: Mass of the person m = 70 kg accelerations $ a=4m/{{s}^{2}},\,g=10m/{{s}^{2}} $ Now, putting the given values in Eq. (i), we have $ T=70\text{ (}10+4\text{)}=70\times 14=980\text{ }N $