A person is standing in an elevator. In which situation, he experiences weight loss ?

Question

A person is standing in an elevator. In which situation, he experiences weight loss ? (A) When the elevator moves upward with constant acceleration (B) When the elevator moves downward with constant acceleration (C) When the elevator moves upward with uniform velocity (D) When the elevator moves downward with uniform velocity

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bbc1b3c952049da4ae1a9547b7fb43d9-.png" /> mg - N = ma ⇒ N = m ( g - a ) ∴ Person experiences weightloss, when acceleration of lift is downward.

Q. A person is standing in an elevator. In which situation, he experiences weight loss ?

When the elevator moves upward with constant acceleration

When the elevator moves downward with constant acceleration

When the elevator moves upward with uniform velocity

When the elevator moves downward with uniform velocity

$m g - N = ma$
$\Rightarrow N = m (g - a)$
$∴$ Person experiences weightloss, when
acceleration of lift is downward.

Q. A person is standing in an elevator. In which situation, he experiences weight loss ?

When the elevator moves upward with constant acceleration

When the elevator moves downward with constant acceleration

When the elevator moves upward with uniform velocity

When the elevator moves downward with uniform velocity

mg−N=ma ⇒N=m(g−a) ∴ Person experiences weightloss, when acceleration of lift is downward.

$m g - N = ma$
$\Rightarrow N = m (g - a)$
$∴$ Person experiences weightloss, when
acceleration of lift is downward.