A person climbs up a stalled escalator in 60 s . If standing on the same but escalator running with constant velocity he takes 40 s. How much time is taken by the person to walk up the moving escalator ?

Question

A person climbs up a stalled escalator in 60 s . If standing on the same but escalator running with constant velocity he takes 40 s. How much time is taken by the person to walk up the moving escalator ? (A) 37 s (B) 27 s (C) 24 s (D) 45 s

Tardigrade Admin · Accepted Answer

60=(d/v textman) 40=(d/ve s) t=(d/v textman+ve s) (1/t)=(v textman/d)+(ve s/d)=(1/60)+(1/40) t=24 sec

Q. A person climbs up a stalled escalator in $60 s$ . If standing on the same but escalator running with constant velocity he takes $40 s$ . How much time is taken by the person to walk up the moving escalator ?

37 s

27 s

24 s

45 s

$60 = \frac{d}{v _{man}}$
$40 = \frac{d}{v _{es}}$
$t = \frac{d}{v _{man} + v _{es}}$
$\frac{1}{t} = \frac{v _{man}}{d} + \frac{v _{es}}{d} = \frac{1}{60} + \frac{1}{40}$
$t = 24 sec$

Q. A person climbs up a stalled escalator in 60s . If standing on the same but escalator running with constant velocity he takes 40s. How much time is taken by the person to walk up the moving escalator ?