A perfect gas at 27° C is heated at constant pressure so as to triple its volume. The temperature of the gas will be

Question

A perfect gas at 27° C is heated at constant pressure so as to triple its volume. The temperature of the gas will be (A) 81° C (B) 900° C (C) 627° C (D) 450° C

Tardigrade Admin · Accepted Answer

At constant pressure V propto T ⇒ (V1/V2)=(T1/T2) ⇒ (V/3 V)=((273 + 27)/T2) ⇒ T2=900K=627° C

Q. A perfect gas at $2 7^{\circ} C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be

$8 1^{\circ} C$

$90 0^{\circ} C$

$62 7^{\circ} C$

$45 0^{\circ} C$

At constant pressure $V \propto T$
$\Rightarrow \frac{V _{1}}{V _{2}} = \frac{T _{1}}{T _{2}}$
$\Rightarrow \frac{V}{3 V} = \frac{( 273 + 27 )}{T _{2}}$
$\Rightarrow T_{2} = 900 K = 62 7^{\circ} C$

Q. A perfect gas at 27∘C is heated at constant pressure so as to triple its volume. The temperature of the gas will be

81∘C

900∘C

627∘C

450∘C