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Physics
A perfect gas at 27° C is heated at constant pressure so as to triple its volume. The temperature of the gas will be
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Q. A perfect gas at $27^\circ C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be
NTA Abhyas
NTA Abhyas 2020
Thermodynamics
A
$81^\circ C$
43%
B
$900^\circ C$
18%
C
$627^\circ C$
29%
D
$450^\circ C$
10%
Solution:
At constant pressure $V \propto T$
$\Rightarrow \frac{V_{1}}{V_{2}}=\frac{T_{1}}{T_{2}}$
$\Rightarrow \frac{V}{3 V}=\frac{\left(273 + 27\right)}{T_{2}}$
$\Rightarrow T_{2}=900K=627^\circ C$