A pendulum with a bob of mass 2 kg is hanging from the ceiling of a trolley as shown in the figure. The trolley is uniformly accelerating with an acceleration a, then (g=10 m / s 2)

Question

A pendulum with a bob of mass 2 kg is hanging from the ceiling of a trolley as shown in the figure. The trolley is uniformly accelerating with an acceleration a, then (g=10 m / s 2) (A) a=6 m / s 2 (B) a=7.5 m / s 2 (C) a=4 m / s 2 (D) a=2.5 m / s 2

Tardigrade Admin · Accepted Answer

a =g tan θ=10 tan 370 =10(3 / 4) ⇒ 7.5 m / s 2 a =g tan θ=10 tan 370 =10(3 / 4) ⇒ 7.5 m / s 2

Q. A pendulum with a bob of mass 2 $k g$ is hanging from the ceiling of a trolley as shown in the figure. The trolley is uniformly accelerating with an acceleration $a$ , then $(g = 10 m / s^{2})$

$a = 6 m / s^{2}$

$a = 7.5 m / s^{2}$

$a = 4 m / s^{2}$

$a = 2.5 m / s^{2}$

$a = g tan θ = 10 tan 3 7^{0}$
$= 10 (3/4)$
$\Rightarrow 7.5 m / s^{2}$ $a = g tan θ = 10 tan 3 7^{0}$
$= 10 (3/4)$
$\Rightarrow 7.5 m / s^{2}$

Q. A pendulum with a bob of mass 2 kg is hanging from the ceiling of a trolley as shown in the figure. The trolley is uniformly accelerating with an acceleration a, then (g=10m/s2)

a=6m/s2

a=7.5m/s2

a=4m/s2

a=2.5m/s2