Question

A particular reaction has a negative value for the free energy change. Then at ordinary temperature

• A. It has a large -ve value for the entropy change
• B. It has a large +ve value for enthalpy change
• C. It has small +ve value for enthalpy change
• D. It has a 4 -ve value for the entropy change and a -ve value for the enthalpy change

Answer 1

Answer: (D)

The reaction is spontaneous ($\Delta$G = -ve). Thus, at ordinary temperature
$\Delta$S = +ve, $\Delta$H = -ve