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Chemistry
A particular reaction has a negative value for the free energy change. Then at ordinary temperature
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Q. A particular reaction has a negative value for the free energy change. Then at ordinary temperature
Thermodynamics
A
It has a large -ve value for the entropy change
15%
B
It has a large +ve value for enthalpy change
24%
C
It has small +ve value for enthalpy change
27%
D
It has a 4 -ve value for the entropy change and a -ve value for the enthalpy change
33%
Solution:
The reaction is spontaneous ($\Delta$G = -ve). Thus, at ordinary temperature
$\Delta$S = +ve, $\Delta$H = -ve