A particular compound of vanadium shows a magnetic moment of 3.86 BM. The oxidation state of vanadium in the compound is hati+ hatj

Question

A particular compound of vanadium shows a magnetic moment of 3.86 BM. The oxidation state of vanadium in the compound is hati+ hatj (A) + 3 (B) 0 (C) +2 (D) +4

Tardigrade Admin · Accepted Answer

Electronic configuration (Z=23) of vanadium is (x/L) M g. Magnetic moment of vanadium 3.86 BM. Therefore, if has 3 unpaired electrons, in the compound, indicating that electrons are removed. As such, the oxidation state of vanadium in +2.

Q. A particular compound of vanadium shows a magnetic moment of $3.86$ BM. The oxidation state of vanadium in the compound is $\hat{i} + \hat{j}$

+ 3

0

+2

+4

Electronic configuration $(Z = 23)$ of vanadium is $\frac{x}{L} M g$ . Magnetic moment of vanadium $3.86 BM$ . Therefore, if has $3$ unpaired electrons, in the compound, indicating that electrons are removed. As such, the oxidation state of vanadium in $+ 2$ .

Q. A particular compound of vanadium shows a magnetic moment of 3.86 BM. The oxidation state of vanadium in the compound is i^+j^​

+ 3

0

+2

+4

Electronic configuration (Z=23) of vanadium is Lx​Mg. Magnetic moment of vanadium 3.86BM. Therefore, if has 3 unpaired electrons, in the compound, indicating that electrons are removed. As such, the oxidation state of vanadium in +2.

Q. A particular compound of vanadium shows a magnetic moment of $3.86$ BM. The oxidation state of vanadium in the compound is $\hat{i} + \hat{j}$

Electronic configuration $(Z = 23)$ of vanadium is $\frac{x}{L} M g$ . Magnetic moment of vanadium $3.86 BM$ . Therefore, if has $3$ unpaired electrons, in the compound, indicating that electrons are removed. As such, the oxidation state of vanadium in $+ 2$ .