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Q. A particular compound of vanadium shows a magnetic moment of $3.86$ BM. The oxidation state of vanadium in the compound is $\hat{i}+\hat{j}$

JamiaJamia 2015

Solution:

Electronic configuration $(Z=23)$ of vanadium is $\frac{x}{L} M g$. Magnetic moment of vanadium $3.86 \,BM$. Therefore, if has $3$ unpaired electrons, in the compound, indicating that electrons are removed. As such, the oxidation state of vanadium in $+2$.