A particle undergoes simple harmonic motion having time period T. The time taken in 3 / 8 th oscillation is

Question

A particle undergoes simple harmonic motion having time period T. The time taken in 3 / 8 th oscillation is (A) (3/8) T (B) (5/8) T (C) (5/12) T (D) (7/12) T

Tardigrade Admin · Accepted Answer

y=(a/2)=a cos ω t=a cos (2 π/T) t or t=(T/6) s So time complete 3 / 8 text th oscillation =(T/4)+(T/6)=(5 T/6)

Q. A particle undergoes simple harmonic motion having time period $T$ . The time taken in $3/8$ th oscillation is

$\frac{3}{8} T$

$\frac{5}{8} T$

$\frac{5}{12} T$

$\frac{7}{12} T$

$y = \frac{a}{2} = a cos ω t = a cos \frac{2 π}{T} t$ or $t = \frac{T}{6} s$
So time complete $3/ 8^{th}$ oscillation
$= \frac{T}{4} + \frac{T}{6} = \frac{5 T}{6}$

Q. A particle undergoes simple harmonic motion having time period T. The time taken in 3/8 th oscillation is

83​T

85​T

125​T

127​T