A particle starts from the point (0,8) metre and moves with uniform velocity of vecv=3 hati m / s. What is the angular momentum of the particle after 5 s about origin (mass of particle is 1 kg )?

Question

A particle starts from the point (0,8) metre and moves with uniform velocity of vecv=3 hati m / s. What is the angular momentum of the particle after 5 s about origin (mass of particle is 1 kg )? (A) -12 hatk kg m 2 / s (B) -24 hatk kg m 2 / s (C) -32 hatk kg m 2 / s (D) -36 hatk kg m 2 / s

Tardigrade Admin · Accepted Answer

L =m v r perp =(1)(3)(8) =24(- hatk) kgm 2 / s

Q. A particle starts from the point $(0, 8)$ metre and moves with uniform velocity of $v = 3 \hat{i} m / s$ . What is the angular momentum of the particle after $5 s$ about origin (mass of particle is $1 k g$ )?

$- 12 \hat{k} k g m^{2} / s$

$- 24 \hat{k} k g m^{2} / s$

$- 32 \hat{k} k g m^{2} / s$

$- 36 \hat{k} k g m^{2} / s$

$L = m v r_{⊥}$
$= (1) (3) (8)$
$= 24 (- \hat{k}) k g m^{2} / s$

Q. A particle starts from the point (0,8) metre and moves with uniform velocity of v=3i^m/s. What is the angular momentum of the particle after 5s about origin (mass of particle is 1kg )?

−12k^kgm2/s

−24k^kgm2/s

−32k^kgm2/s

−36k^kgm2/s