A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time t = 5s?

Question

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time t = 5s? <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d4461958a98c93249666bbb0ea1f441f-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Position of the particle, S = area under graph (time t = 0 to 5s) = (1/2) × 2× 2+2× 2 + 3× 1 = 9m

Q. A particle starts from the origin at time $t = 0$ and moves along the positive $x$ -axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time $t = 5 s$ ?

Position of the particle,
$S =$ area under graph (time $t = 0$ to $5 s)$
$= \frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1 = 9 m$

Q. A particle starts from the origin at time t=0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time t=5s?

Position of the particle, S= area under graph (time t=0 to 5s) =21​×2×2+2×2+3×1=9m

Q. A particle starts from the origin at time $t = 0$ and moves along the positive $x$ -axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time $t = 5 s$ ?

Position of the particle,
$S =$ area under graph (time $t = 0$ to $5 s)$
$= \frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1 = 9 m$