A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be

Question

A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be (A) 110 m/s (B) 55 m/s (C) 550 m/s (D) 660 m/s

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2ab2ff440123d6396228eaa9d83f0a02-.png" /> The area under acceleration-time graph gives change in velocity. As acceleration is zero at the end of 11 sec, we have vmax = Area of Δ OAB = (1/2) × 11 × 10 = 55 m/s

Q. A particle starts from rest. Its acceleration $(a)$ versus time $(t)$ is as shown in the figure. The maximum speed of the particle will be

110 m/s

55 m/s

550 m/s

660 m/s

The area under acceleration-time graph gives change in velocity. As acceleration is zero
at the end of $11 sec,$ we have

$v_{ma x} =$ Area of $Δ O A B$

$= \frac{1}{2} \times 11 \times 10 = 55 m / s$

Q. A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be