A particle starts from a point P at a distance of A / 2 from the mean position O travels towards left as shown in the figure. If the time period of SHM, executed about O is T and amplitude A then the equation of motion of particle is :

Question

A particle starts from a point P at a distance of A / 2 from the mean position O travels towards left as shown in the figure. If the time period of SHM, executed about O is T and amplitude A then the equation of motion of particle is : (A) x=A sin ((2 π/T) t+(π/6)) (B) x=A sin ((2 π/T) t+(5 π/6)) (C) x=A cos ((2 π/T) t+(π/6)) (D) x=A cos ((2 π/T) t+(π/3))

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/31bfb97107252fcff5ef29898f72a21a-.png" /> φ = (5π/6)

Q. A particle starts from a point $P$ at a distance of $A /2$ from the mean position $O &$ travels towards left as shown in the figure. If the time period of SHM, executed about $O$ is $T$ and amplitude $A$ then the equation of motion of particle is :

$x = A sin (\frac{2 π}{T} t + \frac{π}{6})$

$x = A sin (\frac{2 π}{T} t + \frac{5 π}{6})$

$x = A cos (\frac{2 π}{T} t + \frac{π}{6})$

$x = A cos (\frac{2 π}{T} t + \frac{π}{3})$

$ϕ = \frac{5 π}{6}$

Q. A particle starts from a point P at a distance of A/2 from the mean position O& travels towards left as shown in the figure. If the time period of SHM, executed about O is T and amplitude A then the equation of motion of particle is :

x=Asin(T2π​t+6π​)

x=Asin(T2π​t+65π​)

x=Acos(T2π​t+6π​)

x=Acos(T2π​t+3π​)