Question

A particle starts from a point $P$ at a distance of $A / 2$ from the mean position $O \&$ travels towards left as shown in the figure. If the time period of SHM, executed about $O$ is $T$ and amplitude $A$ then the equation of motion of particle is :

• A. $x=A \sin \left(\frac{2 \pi}{T} t+\frac{\pi}{6}\right)$
• B. $x=A \sin \left(\frac{2 \pi}{T} t+\frac{5 \pi}{6}\right)$
• C. $x=A \cos \left(\frac{2 \pi}{T} t+\frac{\pi}{6}\right)$
• D. $x=A \cos \left(\frac{2 \pi}{T} t+\frac{\pi}{3}\right)$

Answer 1

Answer: (B), (D)

$\phi = \frac{5\pi}{6}$