A particle starting from the origin (0,0) moves in a straight line in the (x, y) plane. Its coordinates at a later time are (√3, 3). The path of the particle makes with the x-axis an angle of

Question

A particle starting from the origin (0,0) moves in a straight line in the (x, y) plane. Its coordinates at a later time are (√3, 3). The path of the particle makes with the x-axis an angle of (A) 30° (B) 45° (C) 60° (D) 0°

Tardigrade Admin · Accepted Answer

Draw the situation as shown. O A represents the path of the particle starting from origin O(0,0). Draw a perpendicular from point A to x-axis. Let path of the particle makes an angle θ with the x-axis, then <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7929d00349df48f6ab042e2320abcccd-.png" /> tan θ= slope of line O A =(A B/O B)=(3/√3)=√3 or θ =60°

Q. A particle starting from the origin $(0, 0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates at a later time are $(3, 3)$ . The path of the particle makes with the $x$ -axis an angle of

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$0^{\circ}$

Q. A particle starting from the origin (0,0) moves in a straight line in the (x,y) plane. Its coordinates at a later time are (3​,3). The path of the particle makes with the x-axis an angle of

30∘

45∘

60∘

0∘

Draw the situation as shown. OA represents the path of the particle starting from origin O(0,0). Draw a perpendicular from point A to x-axis. Let path of the particle makes an angle θ with the x-axis, then tanθ= slope of line OA =OBAB​=3​3​=3​ or θ=60∘

Q. A particle starting from the origin $(0, 0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates at a later time are $(3, 3)$ . The path of the particle makes with the $x$ -axis an angle of

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$0^{\circ}$