A particle p is projected vertically upward from a point A. Six seconds later, another particle Q projected upwards from A. Both P and Q reach A simultaneously. The ratio of max heights reached by P and Q =64: 25. Then velocity of projection of Q m / s

Question

A particle p is projected vertically upward from a point A. Six seconds later, another particle Q projected upwards from A. Both P and Q reach A simultaneously. The ratio of max heights reached by P and Q =64: 25. Then velocity of projection of Q m / s (A) 5g (B) 8g (C) 6g (D) 7g

Tardigrade Admin · Accepted Answer

(64/25)=((TB+6/TB))2 TB=10, (2 uQ/g)=10 uQ=5 g

Q. A particle $p$ is projected vertically upward from a point $A$ . Six seconds later, another particle $Q$ projected upwards from A. Both $P$ and $Q$ reach A simultaneously. The ratio of max heights reached by $P$ and $Q = 64 : 25$ . Then velocity of projection of $Q$ ________ $m / s$

5g

8g

6g

7g

$\frac{64}{25} = (\frac{T _{B} + 6}{T _{B}})^{2}$
$T_{B} = 10, \frac{2 u _{Q}}{g} = 10$
$u_{Q} = 5 g$

Q. A particle p is projected vertically upward from a point A. Six seconds later, another particle Q projected upwards from A. Both P and Q reach A simultaneously. The ratio of max heights reached by P and Q=64:25. Then velocity of projection of Q________ m/s

5g

8g

6g

7g

2564​=(TB​TB​+6​)2 TB​=10,g2uQ​​=10 uQ​=5g

Q. A particle $p$ is projected vertically upward from a point $A$ . Six seconds later, another particle $Q$ projected upwards from A. Both $P$ and $Q$ reach A simultaneously. The ratio of max heights reached by $P$ and $Q = 64 : 25$ . Then velocity of projection of $Q$ ________ $m / s$

$\frac{64}{25} = (\frac{T _{B} + 6}{T _{B}})^{2}$
$T_{B} = 10, \frac{2 u _{Q}}{g} = 10$
$u_{Q} = 5 g$