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Q. A particle $p$ is projected vertically upward from a point $A$. Six seconds later, another particle $Q$ projected upwards from A. Both $P$ and $Q$ reach A simultaneously. The ratio of max heights reached by $P$ and $Q =64: 25$. Then velocity of projection of $Q$________ $m / s$

Motion in a Straight Line

Solution:

$\frac{64}{25}=\left(\frac{T_{B}+6}{T_{B}}\right)^{2}$
$T_{B}=10, \frac{2 u_{Q}}{g}=10$
$u_{Q}=5\, g$