A particle of mass m strikes a wall with speed v at an angle 30° with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is

Question

A particle of mass m strikes a wall with speed v at an angle 30° with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is (A) mv (B) (m v/2) (C) 2 mv (D) √3 mv

Tardigrade Admin · Accepted Answer

Impulse = change in momentum applying equation of change in momentum in horizontal direction I =m v sin 30°-(-m v sin 30°) =2 m v((1/2))=m v

Q. A particle of mass $m$ strikes a wall with speed $v$ at an angle $3 0^{\circ}$ with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is

$m v$

$\frac{m v}{2}$

$2 m v$

$3 m v$

Impulse = change in momentum
applying equation of change in momentum in horizontal direction
$I = m v sin 3 0^{\circ} - (- m v sin 3 0^{\circ})$
$= 2 m v (\frac{1}{2}) = m v$

Q. A particle of mass m strikes a wall with speed v at an angle 30∘ with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is

mv

2mv​

2mv

3​mv