A particle of mass m moving with velocity v collides with a stationary particle of mass 2m . The speed of the system, will be:

Question

A particle of mass m moving with velocity v collides with a stationary particle of mass 2m . The speed of the system, will be: (A)  3v  (B)  (v/2)  (C)  v/3  (D)  2v

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/107fe47c72e69c3cd04a487622dc0da7-.png" /> Here m1=m m2=2 m v1=v v2=0 Let the speed of the system after collison =v Using the principle of conservation of linear momentum m1 v1+m2 v2=(m1+m2) v' ⇒ v'=(m v+2 m × 0/m+2 m)=(m v/3 m)=(v/3)

Q. A particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2 m$ . The speed of the system, will be:

$3 v$

$\frac{v}{2}$

$v /3$

$2 v$

Here $m_{1} = m$
$m_{2} = 2 m$
$v_{1} = v$
$v_{2} = 0$
Let the speed of the system after collison $= v$
Using the principle of conservation of linear momentum
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v^{'}$
$\Rightarrow v^{'} = \frac{m v + 2 m \times 0}{m + 2 m} = \frac{m v}{3 m} = \frac{v}{3}$

Q. A particle of mass m moving with velocity v collides with a stationary particle of mass 2m . The speed of the system, will be:

3v

2v​

v/3

2v