A particle of mass m moving towards west with speed v collides with another particle of mass m moving towards south. If two particles stich to each other, the speed of the new particle of mass 2 m will be

Question

A particle of mass m moving towards west with speed v collides with another particle of mass m moving towards south. If two particles stich to each other, the speed of the new particle of mass 2 m will be (A) v √2 (B) (v/√2) (C) (v/2) (D) v

Tardigrade Admin · Accepted Answer

Using conservation of momentum Pi=Pf m v(- hati)+m v(- hatj)=2 m vecv1 |v1|=(v/√2)

Q. A particle of mass $m$ moving towards west with speed $v$ collides with another particle of mass $m$ moving towards south. If two particles stich to each other, the speed of the new particle of mass $2 m$ will be

$v 2$

$\frac{v}{2}$

$\frac{v}{2}$

$v$

Using conservation of momentum
$P_{i} = P_{f}$
$m v (- \hat{i}) + m v (- \hat{j}) = 2 m v^{1}$
$∣ ∣ v^{1} ∣ ∣ = \frac{v}{2}$

Q. A particle of mass m moving towards west with speed v collides with another particle of mass m moving towards south. If two particles stich to each other, the speed of the new particle of mass 2m will be

v2​

2​v​

2v​

v

Using conservation of momentum Pi​=Pf​ mv(−i^)+mv(−j^​)=2mv1 ∣∣​v1∣∣​=2​v​

Q. A particle of mass $m$ moving towards west with speed $v$ collides with another particle of mass $m$ moving towards south. If two particles stich to each other, the speed of the new particle of mass $2 m$ will be

$v 2$

$\frac{v}{2}$

$\frac{v}{2}$

$v$

Using conservation of momentum
$P_{i} = P_{f}$
$m v (- \hat{i}) + m v (- \hat{j}) = 2 m v^{1}$
$∣ ∣ v^{1} ∣ ∣ = \frac{v}{2}$