A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northwards with same speed v. The two particles coalesce on collision. The new particle of mass 2 m will move with velocity

Question

A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northwards with same speed v. The two particles coalesce on collision. The new particle of mass 2 m will move with velocity (A) (v/2) North-East (B) (v/√2) South-West (C) (v/2) North-West (D) (v/√2) North-East

Tardigrade Admin · Accepted Answer

Using momentum conservation

2 m v1=√2 m v v1=(v/√2) North-East

Q. A particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northwards with same speed $v$ . The two particles coalesce on collision. The new particle of mass $2 m$ will move with velocity

$\frac{v}{2}$ North-East

$\frac{v}{2}$ South-West

$\frac{v}{2}$ North-West

$\frac{v}{2}$ North-East

Using momentum conservation

$2 m v^{1} = 2 m v$
$v^{1} = \frac{v}{2}$ North-East

Q. A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northwards with same speed v. The two particles coalesce on collision. The new particle of mass 2m will move with velocity

2v​ North-East

2​v​ South-West

2v​ North-West

2​v​ North-East

Using momentum conservation 2mv1=2​mv v1=2​v​ North-East

Q. A particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northwards with same speed $v$ . The two particles coalesce on collision. The new particle of mass $2 m$ will move with velocity

$\frac{v}{2}$ North-East

$\frac{v}{2}$ South-West

$\frac{v}{2}$ North-West

$\frac{v}{2}$ North-East

Using momentum conservation

$2 m v^{1} = 2 m v$
$v^{1} = \frac{v}{2}$ North-East