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Q. A particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northwards with same speed $v$. The two particles coalesce on collision. The new particle of mass $2\, m$ will move with velocity

Work, Energy and Power

Solution:

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Using momentum conservation
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$2 m v^{1}=\sqrt{2} m v$
$v^{1}=\frac{v}{\sqrt{2}}$ North-East