A particle of mass m is placed at the centre of a uniform spherical shell of mass 3 m and radius R. The gravitational potential on the surface of the shell is

Question

A particle of mass m is placed at the centre of a uniform spherical shell of mass 3 m and radius R. The gravitational potential on the surface of the shell is (A) -(G m/R) (B) -(3 G m/R) (C) -(4 G m/R) (D) -(2 G m/R)

Tardigrade Admin · Accepted Answer

Gravitational potential on the surface of the shell is V= Gravitational potential due to particle (V1) + Gravitational potential due to shell itself (V2) =-(G m/R)+(-(G 3 m/R)) =-(4 G m/R)

Q. A particle of mass $m$ is placed at the centre of a uniform spherical shell of mass $3 m$ and radius $R$ . The gravitational potential on the surface of the shell is

$- \frac{G m}{R}$

$- \frac{3 G m}{R}$

$- \frac{4 G m}{R}$

$- \frac{2 G m}{R}$

Gravitational potential on the surface of the shell is
$V =$ Gravitational potential due to particle $(V_{1})$
+ Gravitational potential due to shell itself $(V_{2})$
$= - \frac{G m}{R} + (- \frac{G 3 m}{R})$
$= - \frac{4 G m}{R}$

Q. A particle of mass m is placed at the centre of a uniform spherical shell of mass 3m and radius R. The gravitational potential on the surface of the shell is

−RGm​

−R3Gm​

−R4Gm​

−R2Gm​