A particle of mass m is moving with a uniform velocity v1 It is given an impulse such that its velocity becomes v2. The impulse is equal to

Question

A particle of mass m is moving with a uniform velocity v1 It is given an impulse such that its velocity becomes v2. The impulse is equal to (A) m[| v2 |-| v1 |] (B) (1/2)m[| v22 |-| v21 |] (C) m[v1 + v2]  (D) m[v2 - v1]

Tardigrade Admin · Accepted Answer

Impulse is a vector quantity and is equal to change in momentum of the body thus, (same as F × t where t is short) Impulse =mv2-mv1=m(v2-v1)

Q. A particle of mass $m$ is moving with a uniform velocity $v_{1}$ It is given an impulse such that its velocity becomes $v_{2} .$ The impulse is equal to

$m [∣ v_{2} ∣ - ∣ v_{1} ∣]$

$\frac{1}{2} m [∣ v_{2}^{2} ∣ - ∣ v_{1}^{2} ∣]$

$m [v_{1} + v_{2}]$

$m [v_{2} - v_{1}]$

Impulse is a vector quantity and is equal to change in momentum of the body thus, (same as $F \times t$ where $t$ is short)
Impulse $= m v_{2} - m v_{1} = m (v_{2} - v_{1})$

Q. A particle of mass m is moving with a uniform velocity v1​ It is given an impulse such that its velocity becomes v2​. The impulse is equal to

m[∣v2​∣−∣v1​∣]

21​m[∣v22​∣−∣v12​∣]

m[v1​+v2​]

m[v2​−v1​]