Question

A particle of mass $m$ executes simple harmonic motion with amplitude $a$ and frequency $v$. The average kinetic energy during its motion from the position of equilibrium to the end is

• A. ${\pi }^{2}m{a}^2{v}^2$
• B. $\frac{1}{4}{\pi }^{2}m{a}^2{v}^2$
• C. $4{\pi }^{2}m{a}^2{v}^2$
• D. $2{\pi }^{2}m{a}^2{v}^2$

Answer 1

Answer: (A)

$\frac{1}{4}m{a}^2{\omega }^2={\pi }^2{f}^{2}m{a}^2$