Question

A particle of mass $m$ executes simple harmonic motion with amplitude $a$ and frequency $v$. The average kinetic energy during its motion from the position of equilibrium to the end is

• A. $\pi^{2}ma^{2}v^{2}$
• B. $\frac{1}{4}\pi^{2}ma^{2}v^{2}$
• C. $4\pi^{2}ma^{2}v^{2}$
• D. $2\pi^{2}ma^{2}v^{2}$

Answer 1

Answer: (A)

$\frac{1}{4}ma^{2}\omega^{2}=\pi^{2}f ^{2}ma^{2}$