A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4/r2) . The momentum of the particle is

Question

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4/r2) . The momentum of the particle is (A) (4 m/r) (B) (2 m/r) (C)  (4 m/√r) (D)  (2 m/√r)

Tardigrade Admin · Accepted Answer

Given, centripetal acceleration = (4/r2) ∴ (v2/r)=(4/r2) or v=(2/√r) Hence, p=(2 m/√r)

Q. A particle of mass $m$ describes a circle of radius $r$ . The centripetal acceleration of the particle is $\frac{4}{r ^{2}}$ . The momentum of the particle is

$\frac{4 m}{r}$

$\frac{2 m}{r}$

$\frac{4 m}{r}$

$\frac{2 m}{r}$

Given, centripetal acceleration = $\frac{4}{r ^{2}}$
$∴ \frac{v ^{2}}{r} = \frac{4}{r ^{2}}$
or $v = \frac{2}{r}$
Hence, $p = \frac{2 m}{r}$

Q. A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is r24​ . The momentum of the particle is

r4m​

r2m​

r​4m​

r​2m​

Given, centripetal acceleration = r24​ ∴rv2​=r24​ or v=r​2​ Hence, p=r​2m​

Q. A particle of mass $m$ describes a circle of radius $r$ . The centripetal acceleration of the particle is $\frac{4}{r ^{2}}$ . The momentum of the particle is

$\frac{4 m}{r}$

$\frac{2 m}{r}$

$\frac{4 m}{r}$

$\frac{2 m}{r}$

Given, centripetal acceleration = $\frac{4}{r ^{2}}$
$∴ \frac{v ^{2}}{r} = \frac{4}{r ^{2}}$
or $v = \frac{2}{r}$
Hence, $p = \frac{2 m}{r}$