A particle of mass m and charge q moving with constant velocity v along positive x direction enters a region containing a uniform magnetic fileld B directed along the negative z direction, extending from x=a to x=b . For the particle to enter the region xb , the minimum value of v is

Question

A particle of mass m and charge q moving with constant velocity v along positive x direction enters a region containing a uniform magnetic fileld B directed along the negative z direction, extending from x=a to x=b . For the particle to enter the region x>b , the minimum value of v is (A) (q b B/m) (B) (q (b - a) B/m) (C) (q a B/m) (D) (q (b + a) B/2 m)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-tuqmmk5b8rt0.png" /> R=(mv/qB)>b-a v=(qB (. b - a .)/m)

$\frac{q b B}{m}$

$\frac{q ( b - a ) B}{m}$

$\frac{q a B}{m}$

$\frac{q ( b + a ) B}{2 m}$

$R = \frac{m v}{qB} > b - a$
$v = \frac{qB ( b - a )}{m}$

Q. A particle of mass m and charge q moving with constant velocity v along positive x direction enters a region containing a uniform magnetic fileld B directed along the negative z direction, extending from x=a to x=b . For the particle to enter the region x>b , the minimum value of v is

mqbB​

mq(b−a)B​

mqaB​

2mq(b+a)B​

R=qBmv​>b−a v=mqB(b−a)​

$\frac{q b B}{m}$

$\frac{q ( b - a ) B}{m}$

$\frac{q a B}{m}$

$\frac{q ( b + a ) B}{2 m}$

$R = \frac{m v}{qB} > b - a$
$v = \frac{qB ( b - a )}{m}$