A particle of mass 5g is moving with a speed of 3√2cms-1 in X-Y plane along the line y = x + 4 . The magnitude of its angular momentum about the origin in gcm2s-1 is

Question

A particle of mass 5g is moving with a speed of 3√2cms-1 in X-Y plane along the line y = x + 4 . The magnitude of its angular momentum about the origin in gcm2s-1 is (A) zero (B) 60 (C) 30 (D) (30/√2)

Tardigrade Admin · Accepted Answer

Given y = x+4 when x = 0, y = 4cm and y = 0,x = - 4cm perpendicular distance OC = OA sin 45° = 4 × (1/√2) = 2 √2 cm Angular momentum = m ν (OC ) = 5 ( 3 √2 ) ( 2 √2 ) = 60 gm cm2 s-1

Q. A particle of mass 5g is moving with a speed of $32 c m s^{- 1}$ in X-Y plane along the line y = x + 4 . The magnitude of its angular momentum about the origin in $g c m^{2} s^{- 1}$ is

zero

60

30

$\frac{30}{2}$

Given $y = x + 4$ when $x = 0, y = 4 c m$ and $y = 0, x = - 4 c m$ perpendicular distance $OC = O A$ sin $4 5^{\circ} = 4 \times \frac{1}{2} = 22 c m$ Angular momentum = $m ν (OC) = 5 (32) (22)$ = $60 g m c m^{2} s^{- 1}$

Q. A particle of mass 5g is moving with a speed of 32​cms−1 in X-Y plane along the line y = x + 4 . The magnitude of its angular momentum about the origin in gcm2s−1 is

zero

60

30

2​30​

Given y=x+4 when x=0,y=4cm and y=0,x=−4cm perpendicular distance OC=OA sin 45∘=4×2​1​=22​cm Angular momentum = mν(OC)=5(32​)(22​) = 60gmcm2s−1

Q. A particle of mass 5g is moving with a speed of $32 c m s^{- 1}$ in X-Y plane along the line y = x + 4 . The magnitude of its angular momentum about the origin in $g c m^{2} s^{- 1}$ is

$\frac{30}{2}$

Given $y = x + 4$ when $x = 0, y = 4 c m$ and $y = 0, x = - 4 c m$ perpendicular distance $OC = O A$ sin $4 5^{\circ} = 4 \times \frac{1}{2} = 22 c m$ Angular momentum = $m ν (OC) = 5 (32) (22)$ = $60 g m c m^{2} s^{- 1}$