A particle of mass 250 g executes a simple harmonic motion under a periodic force F =(-25 x) N. The particle attains a maximum speed of 4 m / s during its oscillation. The amplitude of the motion is cm.

Question

A particle of mass 250 g executes a simple harmonic motion under a periodic force F =(-25 x) N. The particle attains a maximum speed of 4 m / s during its oscillation. The amplitude of the motion is cm. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(1/4) a =-25 x ; a =-100 x ω2=100 ω=10 ω A =4 A =(4/10)=0.4 m A =40 cm

Q. A particle of mass $250 g$ executes a simple harmonic motion under a periodic force $F = (- 25 x) N$ . The particle attains a maximum speed of $4 m / s$ during its oscillation. The amplitude of the motion is __ $c m$ .

$\frac{1}{4} a = - 25 x; a = - 100 x$
$ω^{2} = 100 ω = 10$
$ω A = 4$
$A = \frac{4}{10} = 0.4 m$
$A = 40 c m$

Q. A particle of mass 250g executes a simple harmonic motion under a periodic force F=(−25x)N. The particle attains a maximum speed of 4m/s during its oscillation. The amplitude of the motion is __ cm.

41​a=−25x;a=−100x ω2=100ω=10 ωA=4 A=104​=0.4m A=40cm

Q. A particle of mass $250 g$ executes a simple harmonic motion under a periodic force $F = (- 25 x) N$ . The particle attains a maximum speed of $4 m / s$ during its oscillation. The amplitude of the motion is __ $c m$ .

$\frac{1}{4} a = - 25 x; a = - 100 x$
$ω^{2} = 100 ω = 10$
$ω A = 4$
$A = \frac{4}{10} = 0.4 m$
$A = 40 c m$