A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 × 106 ms -1. The velocity of the particle is

Question

A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 × 106 ms -1. The velocity of the particle is (A) 3 × 10-31 ms -1 (B) 2.7 × 10-21 ms -1 (C) 2.7 × 10-18 ms -1 (D) 9 × 10-2 ms -1

Tardigrade Admin · Accepted Answer

de-Broglie wavelength, λ=(h/m v) As both particle and electrons having same wavelength therefore, their momentum will be equal to ⇒ mp vp=me ve ⇒ vp=(m e ve/mp)=(9.1 × 10-31 × 3 × 106/10-6) ⇒ vp=2.7 × 10-18 m / s

Q. A particle of mass $1 m g$ has the same wavelength as an electron moving with a velocity of $3 \times 1 0^{6} m s^{- 1}$ . The velocity of the particle is

$3 \times 1 0^{- 31} m s^{- 1}$

$2.7 \times 1 0^{- 21} m s^{- 1}$

$2.7 \times 1 0^{- 18} m s^{- 1}$

$9 \times 1 0^{- 2} m s^{- 1}$

Q. A particle of mass 1mg has the same wavelength as an electron moving with a velocity of 3×106ms−1. The velocity of the particle is

3×10−31ms−1

2.7×10−21ms−1

2.7×10−18ms−1

9×10−2ms−1

de-Broglie wavelength, λ=mvh​ As both particle and electrons having same wavelength therefore, their momentum will be equal to ⇒mp​vp​=me​ve​ ⇒vp​=mp​me​ve​​=10−69.1×10−31×3×106​ ⇒vp​=2.7×10−18m/s

Q. A particle of mass $1 m g$ has the same wavelength as an electron moving with a velocity of $3 \times 1 0^{6} m s^{- 1}$ . The velocity of the particle is

$3 \times 1 0^{- 31} m s^{- 1}$

$2.7 \times 1 0^{- 21} m s^{- 1}$

$2.7 \times 1 0^{- 18} m s^{- 1}$

$9 \times 1 0^{- 2} m s^{- 1}$