A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in the figure. If it starts its journey from rest at x=0 , its velocity at x=12 m is

Question

A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in the figure. If it starts its journey from rest at x=0 , its velocity at x=12 m is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-kitunlkw2tnnyjb3.jpg" /> (A) 0ms- 1 (B) 40ms- 1 (C) 20√2 textm s- 1 (D) 20ms- 1

Tardigrade Admin · Accepted Answer

Net work done by the force = area under the curve

= \frac{4 \times 10}{2} + 4 \times 10 + \frac{4 \times 10}{2} = 80 J

According to work-energy theorem
ΔK.E. = W_net

\frac{1}{2} m v^{2} - 0 = 80 or \frac{1}{2} \times 0 \cdot 1 v^{2} = 80

v = 1600 = 40 m s^{- 1}

Q. A particle of mass $0.1 k g$ is subjected to a force which varies with distance as shown in the figure. If it starts its journey from rest at $x = 0$ , its velocity at $x = 12 m$ is

$0 m s^{- 1}$

$40 m s^{- 1}$

$202 m s^{- 1}$

$20 m s^{- 1}$

Net work done by the force = area under the curve
$= \frac{4 \times 10}{2} + 4 \times 10 + \frac{4 \times 10}{2} = 80 J$
According to work-energy theorem
ΔK.E. = W_net
$\frac{1}{2} m v^{2} - 0 = 80 or \frac{1}{2} \times 0 \cdot 1 v^{2} = 80$
$v = 1600 = 40 m s^{- 1}$

Q. A particle of mass 0.1kg is subjected to a force which varies with distance as shown in the figure. If it starts its journey from rest at x=0 , its velocity at x=12m is

0ms−1

40ms−1

202​m s−1

20ms−1