A particle of mass 0.01 kg is projected with velocity v = 2 hati m s-1 from point (x = 0, y = 20) . After 2 seconds, its position coordinates are

Question

A particle of mass 0.01 kg is projected with velocity v = 2 hati m s-1 from point (x = 0, y = 20) . After 2 seconds, its position coordinates are (A) (4, 0) (B) (20, 4) (C) (0, 4) (D) (4, 20)

Tardigrade Admin · Accepted Answer

The particle is moving only along x-axis, whereas the location along y-axis does not change.
Displacement of particle along x-axis in time

t = 2 s

is

2 \times 2 = 4

units.
Therefore, position coordinates of particle after

2 s

is

(4, 20)

.

Q. A particle of mass 0.01kg is projected with velocity v=2i^ms−1 from point (x=0,y=20) . After 2 seconds, its position coordinates are

(4, 0)

(20, 4)

(0, 4)

(4, 20)

The particle is moving only along x-axis, whereas the location along y-axis does not change. Displacement of particle along x-axis in time t=2s is 2×2=4 units. Therefore, position coordinates of particle after 2s is (4,20).

Q. A particle of mass $0.01 k g$ is projected with velocity $v = 2 \hat{i} m s^{- 1}$ from point $(x = 0, y = 20)$ . After 2 seconds, its position coordinates are

The particle is moving only along x-axis, whereas the location along y-axis does not change.
Displacement of particle along x-axis in time $t = 2 s$ is $2 \times 2 = 4$ units.
Therefore, position coordinates of particle after $2 s$ is $(4, 20)$ .