A particle of charge -16 × 10-18C moving with velocity 10 ms-1 along the x -axis enters a region where a magnetic field of induction B is along the y-axis and an electric field of magnitude text1 text0 text4 textV/m is along the negative z-axis. If the charged particle continues moving along the x -axis, the magnitude of B is

Question

A particle of charge -16 × 10-18C moving with velocity 10 ms-1 along the x -axis enters a region where a magnetic field of induction B is along the y-axis and an electric field of magnitude text1 text0 text4 textV/m is along the negative z-axis. If the charged particle continues moving along the x -axis, the magnitude of B is (A)  1016 Wb/m2  (B)  105 Wb/m2  (C)  103 Wb/m2  (D)  10-3 Wb/m2

Tardigrade Admin · Accepted Answer

As particle is moving without deviation, therefore Eq=Bqv ∴ B=(E/v)=(104/10) =103Wb/m2

$10^{16} Wb / m^{2}$

$10^{5} Wb / m^{2}$

$10^{3} Wb / m^{2}$

$10^{- 3} Wb / m^{2}$

As particle is moving without deviation, therefore $Eq = Bq v$ $∴$ $B = \frac{E}{v} = \frac{10 ^{4}}{10}$ $= 10^{3} Wb / m^{2}$

1016Wb/m2

105Wb/m2

103Wb/m2

10−3Wb/m2

As particle is moving without deviation, therefore Eq=Bqv ∴ B=vE​=10104​ =103Wb/m2

$10^{16} Wb / m^{2}$

$10^{5} Wb / m^{2}$

$10^{3} Wb / m^{2}$

$10^{- 3} Wb / m^{2}$

As particle is moving without deviation, therefore $Eq = Bq v$ $∴$ $B = \frac{E}{v} = \frac{10 ^{4}}{10}$ $= 10^{3} Wb / m^{2}$