A particle moving with velocity v having specific charge (.q/m.) enters a region of magnetic field B having width d=(3 mv/5 qB) at angle 53° to the boundary of magnetic field. Find the angle θ in the diagram.

Question

A particle moving with velocity v having specific charge (.q/m.) enters a region of magnetic field B having width d=(3 mv/5 qB) at angle 53° to the boundary of magnetic field. Find the angle θ in the diagram. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-ts7y2zlc9mabkzou.jpg" /> (A) 37° (B) 60° (C) 90° (D) none

Tardigrade Admin · Accepted Answer

R=(mv/qB) d=Rcos53Â° <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-ts7y2zlc9mabs5sv.jpg" /> ⇒ θ =90Â°

Q. A particle moving with velocity $v$ having specific charge $(q / m)$ enters a region of magnetic field $B$ having width $d = \frac{3 m v}{5 qB}$ at angle $5 3^{\circ}$ to the boundary of magnetic field. Find the angle $θ$ in the diagram.

$37°$

$60°$

$90°$

none

$R = \frac{m v}{qB}$
$d = R cos 53°$

$\Rightarrow θ = 90°$

Q. A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width d=5qB3mv​ at angle 53∘ to the boundary of magnetic field. Find the angle θ in the diagram.

37°

60°

90°