Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A particle moves with a velocity (5 hat i -3 hat j +6 hat k ) m / s under the influence of a constant force vec F =10 hat i +10 hat j +20 hat k N. The instantaneous power applied to the particle is
Q. A particle moves with a velocity
(
5
i
^
−
3
j
^
+
6
k
^
)
m
/
s
under the influence of a constant force
F
=
10
i
^
+
10
j
^
+
20
k
^
N
. The instantaneous power applied to the particle is
1885
203
AMU
AMU 2006
Report Error
A
200 J/s
B
40 J/s
C
140 J/s
D
170 J/s
Solution:
v
=
(
5
i
^
−
3
j
^
+
6
k
^
)
m
/
s
F
=
(
10
i
^
+
10
j
^
+
20
k
^
)
N
∴
Power
P
=
F
⋅
v
=
(
10
i
^
+
10
j
^
+
20
k
^
)
⋅
(
5
i
^
−
3
j
^
+
6
k
^
)
=
50
−
30
+
120
=
140
J
/
s