A particle moves towards east for 2 sec with velocity 15 m / s and move towards north for 8 sec with velocity 5 m / s. Then average velocity of the particle is :

Question

A particle moves towards east for 2 sec with velocity 15 m / s and move towards north for 8 sec with velocity 5 m / s. Then average velocity of the particle is : (A) 1 m/s (B) 5 m/s (C) 7 m/s (D) 10 m/s

Tardigrade Admin · Accepted Answer

Distance convered towards east =2 × 15=30 m Distance covered towards north =8 × 5=40 m <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2da4e0ea52c326881a454d7d0c25b85f-.png" /> Total displacement =√402+302=50 m Average velocity =( text total displacement/ text total time ) =(50/2+8)=5 m / s

Q. A particle moves towards east for $2 sec$ with velocity $15 m / s$ and move towards north for $8 sec$ with velocity $5 m / s$ . Then average velocity of the particle is :

1 m/s

5 m/s

7 m/s

10 m/s

Distance convered towards east
$= 2 \times 15 = 30 m$
Distance covered towards north
$= 8 \times 5 = 40 m$

Total displacement $= 4 0^{2} + 3 0^{2} = 50 m$
Average velocity $= \frac{total displacement}{total time}$
$= \frac{50}{2 + 8} = 5 m / s$

Q. A particle moves towards east for 2sec with velocity 15m/s and move towards north for 8sec with velocity 5m/s. Then average velocity of the particle is :