Q.
A particle moves in a circle of radius 30cm . Its liner speed is given by v=2t, where t is in second and v in ms−1 . Find out its radial and tangential acceleration at t=3s , respectively,
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NTA AbhyasNTA Abhyas 2020Laws of Motion
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Solution:
Given that, the radius of the circle, r=30cm=0.3m linearspeedv=2t Now,radialaccelerationaR=rv2=0.3(2t)2 att=3s aR=0.3(2×3)2 0.336=120ms−2 oraR=120ms−2 andtangentialaccelerationaT=dtdv=dtd(2t)=2(ms)−2