A particle moves in a circle of radius 0.5m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 2ms- 1 to 4ms- 1 in 4seconds ?

Question

A particle moves in a circle of radius 0.5m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 2ms- 1 to 4ms- 1 in 4seconds ? (A) 1 rads- 2 (B) 2rads- 2 (C) 4rads- 2 (D) 0rads- 2

Tardigrade Admin · Accepted Answer

The tangential acceleration of the particle is at=(d v/d t)=(4.0 - 2.0/4.0) =0.5ms- 2 The angular acceleration is α =(at/r)=(0.5/0.5)=1rads- 2

Q. A particle moves in a circle of radius $0.5 m$ at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from $2 m s^{- 1}$ to $4 m s^{- 1}$ in $4 seco n d s$ ?

$1$ $r a d s^{- 2}$

$2 r a d s^{- 2}$

$4 r a d s^{- 2}$

$0 r a d s^{- 2}$

The tangential acceleration of the particle is
$a_{t} = \frac{d v}{d t} = \frac{4.0 - 2.0}{4.0}$
$= 0.5 m s^{- 2}$
The angular acceleration is
$α = \frac{a _{t}}{r} = \frac{0.5}{0.5} = 1 r a d s^{- 2}$

Q. A particle moves in a circle of radius 0.5m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 2ms−1 to 4ms−1 in 4seconds ?

1 rads−2

2rads−2

4rads−2

0rads−2