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Question
Physics
A particle moves from position r1=(3 hati + 2 hatj - 6 hatk) m to position r2=(14 hati + 13 hatj + 9 hatk) m under the action of a force (4 hati + hatj - 3 hatk) N, then the work done is
Q. A particle moves from position
r
1
=
(
3
i
^
+
2
j
^
−
6
k
^
)
m
to position
r
2
=
(
14
i
^
+
13
j
^
+
9
k
^
)
m
under the action of a force
(
4
i
^
+
j
^
−
3
k
^
)
N
,
then the work done is
1188
163
NTA Abhyas
NTA Abhyas 2022
Report Error
A
46
J
B
56
J
C
86
J
D
10
J
Solution:
Given,
r
1
=
(
3
i
^
+
2
j
^
−
6
k
^
)
m
r
2
=
(
14
i
^
+
13
j
^
+
9
k
^
)
m
F
=
(
4
i
^
+
j
^
−
3
k
^
)
N
Displacement,
s
=
r
2
−
r
1
=
(
14
i
^
+
13
j
^
+
9
k
^
)
−
(
3
i
^
+
2
j
^
−
6
k
^
)
or,
s
=
11
i
^
+
11
j
^
+
15
k
^
∴
Work done,
W
=
F
.
s
=
(
4
i
^
+
j
^
−
3
k
^
)
⋅
(
11
i
^
+
11
j
^
+
15
k
^
)
=
44
+
11
−
45
or
W
=
10
J