Tardigrade
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Tardigrade
Question
Physics
A particle moves along a circle of radius R = 1 m so that its radius vector vecr relative to a point on its circumference rotates with the constant angular velocity ω=2 rad/s. The linear speed of the particle is
Q. A particle moves along a circle of radius
R
=
1
m
so that its radius vector
r
relative to a point on its circumference rotates with the constant angular velocity
ω
=
2
r
a
d
/
s
. The linear speed of the particle is
2227
204
Motion in a Plane
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A
4 m/s
15%
B
2 m/s
56%
C
1 m/s
10%
D
0.5 m/s
19%
Solution:
Angular velocity about center
=
2
(angular velocity about any point on its circumference)
or
ω
=
2
(
2
)
rad/s
or
ω
=
2
rad/s
now
v
=
r
ω
=
(
1
)
(
4
)
=
4
m
/
s