A particle moves along a circle of radius ((20/π)) m with constant tangential acceleration. If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is

Question

A particle moves along a circle of radius ((20/π)) m with constant tangential acceleration. If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is (A) 40 m/s2 (B) 640 π m/s2 (C) 160 π m/s2 (D) 40 π m/s2

Tardigrade Admin · Accepted Answer

r=(20/π) m , v=80 m / s , θ=2 rev =4 π rad From equation ω2=ω02+2 α θ (ω0=0) ω2=2 α θ(ω=(v/r) text and a=r α) a=(v2/2 r θ)=40 m / s 2

Q. A particle moves along a circle of radius $(\frac{20}{π}) m$ with constant tangential acceleration. If the velocity of the particle is $80 m / s$ at the end of the second revolution after motion has begun, the tangential acceleration is

$40 m / s^{2}$

$640 π m / s^{2}$

$160 π m / s^{2}$

$40 π m / s^{2}$

$r = \frac{20}{π} m, v = 80 m / s, θ = 2 re v = 4 π r a d$
From equation $ω^{2} = ω_{0}^{2} + 2 α θ (ω_{0} = 0)$
$ω^{2} = 2 α θ (ω = \frac{v}{r} and a = r α)$
$a = \frac{v ^{2}}{2 r θ} = 40 m / s^{2}$

Q. A particle moves along a circle of radius (π20​)m with constant tangential acceleration. If the velocity of the particle is 80m/s at the end of the second revolution after motion has begun, the tangential acceleration is

40m/s2

640πm/s2

160πm/s2

40πm/s2