A particle is revolving at 1200 rpm in a circle of radius 30 cm. Then, its acceleration is

Question

A particle is revolving at 1200 rpm in a circle of radius 30 cm. Then, its acceleration is (A) 1600 ms -2 (B) 4740 ms -2 (C) 2370 ms -2 (D) 5055 ms -2

Tardigrade Admin · Accepted Answer

Given, v=1200 rpm =(1200/60) rps, r=30 cm =(30/100) m Acceleration of the particle = Centripetal acceleration =ω2 r=(2 π v)2 r =(2 × (22/7) × (1200/60))2 × (30/100) ≈ 4740 ms -2

Q. A particle is revolving at $1200 r p m$ in a circle of radius $30 c m$ . Then, its acceleration is

$1600 m s^{- 2}$

$4740 m s^{- 2}$

$2370 m s^{- 2}$

$5055 m s^{- 2}$

Given, $v = 1200 r p m = \frac{1200}{60} r p s$ ,
$r = 30 c m = \frac{30}{100} m$
Acceleration of the particle
$=$ Centripetal acceleration $= ω^{2} r = (2 π v)^{2} r$
$= (2 \times \frac{22}{7} \times \frac{1200}{60})^{2} \times \frac{30}{100} \approx 4740 m s^{- 2}$

Q. A particle is revolving at 1200rpm in a circle of radius 30cm. Then, its acceleration is

1600ms−2

4740ms−2

2370ms−2

5055ms−2