A particle is projected from ground with speed 80 m / s at an angle 30° with horizontal from ground. The magnitude of average velocity of particle in time interval t=2 s to t=6 s is [Take .g=10 m / s 2]

Question

A particle is projected from ground with speed 80 m / s at an angle 30° with horizontal from ground. The magnitude of average velocity of particle in time interval t=2 s to t=6 s is [Take .g=10 m / s 2] (A) 40 √2 m / s (B) 40 m / s (C) Zero (D) 40 √3 m / s

Tardigrade Admin · Accepted Answer

Average velocity of the projectile when it is at the same vertical height is: u cos θ. ⇒ 80 × cos 30° ⇒ 40 ms -1

Q. A particle is projected from ground with speed $80 m / s$ at an angle $3 0^{\circ}$ with horizontal from ground. The magnitude of average velocity of particle in time interval $t = 2 s$ to $t = 6 s$ is [Take $g = 10 m / s^{2}]$

$402 m / s$

$40 m / s$

Zero

$403 m / s$

Average velocity of the projectile when it is at the same vertical height is : $u cos θ$ .
$\Rightarrow 80 \times cos 3 0^{\circ}$
$\Rightarrow 40 m s^{- 1}$

Q. A particle is projected from ground with speed 80m/s at an angle 30∘ with horizontal from ground. The magnitude of average velocity of particle in time interval t=2s to t=6s is [Take g=10m/s2]

402​m/s

40m/s