A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be

Question

A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be (A) 4000 / 3 m (B) 2000 / 3 m (C) 1000 / 3 m (D) 2500 / 3 m

Tardigrade Admin · Accepted Answer

150=100 t+(1/2) 10 t2 ; t=10 sec x=(400/3) t=(4000/3) m

Q. A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be

$4000/3 m$

$2000/3 m$

$1000/3 m$

$2500/3 m$

$150 = 100 t + \frac{1}{2} 10 t^{2}; t = 10 sec$
$x = \frac{400}{3} t = \frac{4000}{3} m$

Q. A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be

4000/3m

2000/3m

1000/3m

2500/3m

150=100t+21​10t2;t=10sec x=3400​t=34000​m

$4000/3 m$

$2000/3 m$

$1000/3 m$

$2500/3 m$

$150 = 100 t + \frac{1}{2} 10 t^{2}; t = 10 sec$
$x = \frac{400}{3} t = \frac{4000}{3} m$