A particle is moving with constant speed over circle x2 + y2 = 50, with speed √10 m/s. Acceleration of the particle, when it is at point (5, 5) is (in m/s2)

Question

A particle is moving with constant speed over circle x2 + y2 = 50, with speed √10 m/s. Acceleration of the particle, when it is at point (5, 5) is (in m/s2) (A)  hati- hatj (B) - hati- hatj (C) (1/√2) hati -(1/√2) hatj (D) (-1/√2) hati -(1/√2) hatj

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/47d1d441b1480fd83a27336c0a5eac9b-.png" /> x2 + y2 = r2 ⇒ r = √50 = 5√2 vecac = (u2/r) = ((√10)2/5√2) = √2 Resolve it into components to get vecac = - hati - hatj

Q. A particle is moving with constant speed over circle $x^{2} + y^{2} = 50$ , with speed $10 m / s$ . Acceleration of the particle, when it is at point $(5, 5)$ is (in $m / s^{2}$ )

$\hat{i} - \hat{j}$

$- \hat{i} - \hat{j}$

$\frac{1}{2} \hat{i} - \frac{1}{2} \hat{j}$

$\frac{- 1}{2} \hat{i} - \frac{1}{2} \hat{j}$

$x^{2} + y^{2} = r^{2}$
$\Rightarrow r = 50$
$= 52$
$a_{c} = \frac{u ^{2}}{r}$
$= \frac{( 10 ) ^{2}}{5 2} = 2$
Resolve it into components to get
$a_{c} = - \hat{i} - \hat{j}$

Q. A particle is moving with constant speed over circle x2+y2=50, with speed 10​m/s. Acceleration of the particle, when it is at point (5,5) is (in m/s2)

i^−j^​

−i^−j^​

2​1​i^−2​1​j^​

2​−1​i^−2​1​j^​