A particle is moving with a constant speed v in a circle. What is the magnitude of average velocity after half rotation ?

Question

A particle is moving with a constant speed v in a circle. What is the magnitude of average velocity after half rotation ? (A) 2v (B) (2v/π) (C) (v/2) (D) (v/2π)

Tardigrade Admin · Accepted Answer

We are given that a particle is moving with a constant speed ν in the circle so the time taken to cover the complete circle would be equal to T = (2π r/ν) hence the time taken to cover half the rotation would be equal to T1/2 = (2π r/2ν) = (π r/ν) , hence the magnitude of average velocity after half rotation on would be equal to νav = (2r/(π r)ν) = (2ν/π)

Q. A particle is moving with a constant speed $v$ in a circle. What is the magnitude of average velocity after half rotation ?

$2 v$

$\frac{2 v}{π}$

$\frac{v}{2}$

$\frac{v}{2 π}$

Q. A particle is moving with a constant speed v in a circle. What is the magnitude of average velocity after half rotation ?

2v

π2v​

2v​

2πv​

Q. A particle is moving with a constant speed $v$ in a circle. What is the magnitude of average velocity after half rotation ?

$2 v$

$\frac{2 v}{π}$

$\frac{v}{2}$

$\frac{v}{2 π}$